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Thursday, 21 April 2016

WAEC MATHEMATICS THEORY ANSWER

WAEC MATHEMATICS ANSWER ================================ ============================. 100% VERIFIED OBJ ANSWERS CLICK IMAGE ABOVE TWICE TO VIEW.. GOODLUCK

2) ii Area if cross-section =Area of rectangle PQRU-Area of semi-circle =(PUxPQ) - pie ITSI/4 =(4x11)-22/7x7/4 =44-22/4 =44-5.5 =38.5m^2

(3b) h=7cm T=462cm^2 T=pie sqr + 2 pie rH 462= pie( r ^2 +2*7*r) 462/3.142 =r sqr= =14r r sqr+ 14r=147 r sqr +14r- 147=0 r= 14+-( (sqr(14))-4*1*147)/2*1 r=-(14 +-(196-4))/2 r=(-14+_12)/2 r=(-14+12)/2 or r=2/2 =1cm

(4a) Pr(3)=x/total total=25+30+x+28+40+32 =155+x 0.225=x/155+ x =34.875+0.225x=x x-0.225x=34.875 =0.775x=34.875 degree x=34.875/0.775 =45

(4b) Pr(even)=30+28+40+32 =90 Pr(even)=90/200=9/20 Pr(prime no)=25=30+45+40 =140 Pr(prime no)=140/200=14/20 Pr(even or prime)=9/20 + 14/20

5a) Area of triangle=1/2bh where h=6 :. 1/2*6/1*b/1=36 6b/2=36/1 6b=72 B=72/6

Base of angle PSR=12cm Since |TS| //PQ QR=PR-PQ QR=12-8 QR=4cm

5b) Draw d triangle From angle ABC, to get |BC| Tan60/1=10cm/|BC| |BC|=10.65/tan60 |BC|=10.65/1.7321 =6.1486 =6.15m

Hence |BC|=|DE| From angle AED, to get |AE|

Draw d diagram |AB|=6.15tan45 6.15*1 =6.15m There4, th height of the tree =10.65-6.15 =4.50m ==========================

8a)

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